[2021 KAKAO BLIND RECRUITMENT] 신규 아이디 추천

10:48 시작, 11:39 정답!

문제 설명

https://school.programmers.co.kr/learn/courses/30/lessons/72410?language=python3

프로그래머스

문제 풀이

def solution(new_id):
    answer = ''
    
    # 1단계
    new_id = new_id.lower()
    
    # 2단계
    not_available = [i for i in '~!@#$%^&*()=+[{]}:?,<>/']
    for s in new_id:
        if s not in not_available:
            answer+=s
    # 3단계
    answer_3 = ''
    cnt = 0
    for s in answer:
        if s != '.':
            cnt = 0
        if (s == '.') and (cnt == 0):
            cnt += 1 
        elif (s == '.') and (cnt >= 1):
            continue
        answer_3 += s
        
    # 4단계
    if (len(answer_3) > 0) and (answer_3[0] == '.'):
        answer_3 = answer_3[1:]
    if (len(answer_3) > 0) and (answer_3[-1] == '.'):
        answer_3 = answer_3[:-1]
        
    # 5단계
    if len(answer_3) == 0:
        answer_3 = 'a'
        
    # 6단계
    if len(answer_3) >= 16:
        answer_3 = answer_3[:15]
        
    # 6-2단계
    if (len(answer_3) > 0) and (answer_3[-1] == '.'):
        answer_3 = answer_3[:-1]
        
    # 7단계
    while len(answer_3) <= 2:
        answer_3+=answer_3[-1]
            
    return answer_3

채점 결과

---

다른 사람 풀이

def solution(new_id):
    answer = ''
    # 1
    new_id = new_id.lower()
    # 2
    for c in new_id:
        if c.isalpha() or c.isdigit() or c in ['-', '_', '.']:
            answer += c
    # 3
    while '..' in answer:
        answer = answer.replace('..', '.')
    # 4
    if answer[0] == '.':
        answer = answer[1:] if len(answer) > 1 else '.'
    if answer[-1] == '.':
        answer = answer[:-1]
    # 5
    if answer == '':
        answer = 'a'
    # 6
    if len(answer) > 15:
        answer = answer[:15]
        if answer[-1] == '.':
            answer = answer[:-1]
    # 7
    while len(answer) < 3:
        answer += answer[-1]
    return answer

다른 사람 풀이 채점 결과

 

문제 출처 : 프로그래머스/ Lv1/ 파이썬/ 신규 아이디 추천